/^creative ^commor ISSN 1855-3966 (printed edn.), ISSN 1855-3974 (electronic edn.) Search for the end of a path in the • -dimensional grid and in other graphs Daniel Gerbner ' Hungarian Academy of Sciences, AlfrédRényi Institute of Mathematics, P.O.B. 127, Budapest H-1364, Hungary Balazs Keszegh ' Hungarian Academy of Sciences, Alfred Renyi Institute of Mathematics, P.O.B. 127, Budapest H-1364, Hungary DOmOtor Palvolgyi ' Department of Pure Mathematics and Mathematical Statistics, University of Cambridge, UK Günter Rote ' Freie Universität Berlin, Institut für Informatik, Takustraße 9,14195 Berlin, Germany Gabor Wiener ' Department of Computer Science and Information Theory, Budapest University of Technology and Economics, Muegyetem rkp. 3., H-1111, Budapest, Hungary Received 29 December 2014, accepted 30 Aügüst 2016, published online 21 January 2017 ' Supported by the National Research, Development and Innovation Office - NKFIH, grant no. PD 109537 and by the Janos Bolyai Research Scholarship of the Hungarian Academy of Sciences. ' Supported by the National Research, Development and Innovation Office - NKFIH, grant no. PD 108406, NN 102029 (EUROGIGA project GraDR 10-EuroGIGA-OP-003), NK 78439, K 116769, by the Janos Bolyai Research Scholarship of the Hungarian Academy of Sciences, and DAAD. ' Supported by the National Research, Development and Innovation Office - NKFIH, grant no. PD 104386 and NN 102029 (EUROGIGA project GraDR 10-EuroGIGA-OP-003), the Janos Bolyai Research Scholarship of the Hungarian Academy of Sciences, and by the Marie Sklodowska-Curie action of the EU, under grant IF 660400. ' Supported by the ESF EUROCORES programme EuroGIGA-VORONOI, Deutsche Forschungsgemeinschaft (DFG): RO 2338/5-1. Supported by the National Research, Development and Innovation Office - NKFIH, grant no. 108947, and the Janos Bolyai Research Scholarship of the Hungarian Academy of Sciences. ©® This work is licensed under http://creativecommons.org/licenses/by/3.0/ 301 Ars Math. Contemp. 12 (2017) 383-413 Abstract We consider the worst-case query complexity of some variants of certain •• •• - complete search problems. Suppose we are given a graph • and a vertex....... We denote the directed graph obtained from • by directing all edges in both directions by • '. • is a directed subgraph of • ' which is unknown to us, except that it consists of vertex-disjoint directed paths and cycles and one of the paths originates in •. Our goal is to find an endvertex of a path by using as few queries as possible. A query specifies a vertex ......, and the answer is the set of the edges of • incident to •, together with their directions. We also show lower bounds for the special case when • consists of a single path. Our proofs use the theory of graph separators. Finally, we consider the case when the graph • is a grid graph. In this case, using the connection with separators, we give asymptotically tight bounds as a function of the size of the grid, if the dimension of the grid is considered as fixed. In order to do this, we prove a separator theorem about grid graphs, which is interesting on its own right. Keywords: Separator, graph, search, grid. Math. Subj. Class.: 90B40, 05C85 1 Introduction This paper deals with the following search problem. We are given a simple, undirected, connected graph • and a vertex....... We denote the directed graph obtained from • by directing all edges in both directions by • '. Let • be a directed subgraph of • ', which is the vertex-disjoint union of a directed path starting at • and possibly some other directed paths and cycles. • is unknown to us, and our goal is to identify an endvertex of a directed path. We may query a vertex •, and as an answer, we learn the edges of • incident to • together with their directions. In particular, if the answer is only one incoming edge, then we know that • is an endvertex. We analyze the minimum number of queries that are necessary in the worst case. We give lower bounds in the more restrictive model where we know • is one directed path. Note that if instead of looking for an endvertex, we look for an ending or a starting vertex of a path (different from •), then this model still gives a lower bound for this easier problem. In Section 4 we mention some additional models. Denote by • •• • the minimum number of queries needed to find an endvertex in the worst case for any • • • . If we know that • is one directed path, denote this quantity by • ♦ • • • Biseparators and multiseparators. To state some of our results we need to define separators of graphs. This notion can be defined in two different ways and both definitions are widely used. Here we distinguish between the two definitions. E-mail addresses: gerbner.daniel@renyi.mta.hu (Daniel Gerbner), keszegh.balazs@renyi.mta.hu (Balazs Keszegh), dom@cs.elte.hu (Domotor Palvolgyi), rote@inf.fu-berlin.de (Giinter Rote), wiener@cs.bme.hu (Gabor Wiener) D. Gerbner et al.: Search for the end of a path in the • -dimensional grid and in other graphs 303 Definition 1.1. 1. Given a graph......., a subset • • • is called an • -biseparator of • if • • • can be divided into two parts, • and • , such that there are no edges between • and • , and both have cardinality at most • •• •. 2. Given a graph......., a subset • • • is called an • -multiseparator of • if every connected component of • • • has cardinality at most • •• •. Note that • or • in the definition of a biseparator can be empty: we do not require • • • to be disconnected. Small biseparators make sense only for...... Given these definitions, when we write separator, it can mean either a biseparator or a multiseparator, as in many cases it makes no difference. In the literature, the notation • •• «-separator can also be found, where • •• • is an upper bound on the cardinality of • in terms of the number • of vertices. In this paper it is more straightforward to fix • and then look for the smallest • -separator. Therefore, we let •'.'•• • be the minimum cardinality of an • -biseparator in • and •' •• • be the minimum cardinality of an • -multiseparator in • . It follows from the definitions that every • -biseparator is an • -multiseparator, and thus • '.....' •• •. In many cases they are of the same order of magnitude. In particular, if we have a bound •'.......' • for a class of graphs which is closed under taking subgraphs for some • • • and for some arbitrary • • •, we get the same asymptotic bound on •;.'.•• •, by iteratively separating one of the components. However, there are cases when multiseparators are much smaller than biseparators. For example, if • consists of three disjoint cliques of equal size, all connected to a degree-three vertex, then • 1....... but •''........... For any tree, • 1.......but it is not hard to show that for a complete ternary tree, •I'............, see Appendix A. Finally, if we consider a class of graphs closed under taking subgraphs, by repeatedly refining the separation, then it is obvious that •'.••• and •'..•• • have the same order of magnitude for any two constants • and • '. Results. Our main result establishes a connection between the biseparators and the search complexity for general graphs. Theorem 1.2. For any connected graph • with at least 2 vertices, we have •''.•• • • •p •••• • • • • We can prove an upper bound of the same order of magnitude, if every subgraph has small multiseparators. Note that when bounding • •• •, • "•• •, the larger of the separators, gives the lower bound and •' •• •, the smaller one, gives the almost matching upper bound, which implies that indeed for a large class of graphs •"•• • and •' •• • have the same order of magnitude. Theorem 1.3. Let.......be constants, let • be a monotone function, and let • be a graph such that any subgraph • of • has an • -multiseparator of size at most.......... If...........for all • • 0,then • • • • • • • 304 Ars Math. Contemp. 12 (2017) 383-413 The condition on • could be interpreted as having "at least polynomial growth". The condition is fulfilled by the function............' if and only if...... • .To put it differently, if • and • • • are given, the theorem applies with • •• • '. We also study the search problem for the special case of grid graphs. Definition 1.4. Let • be a positive integer and ••....... • a sequence of positive integers. The • -dimensional grid graph of side length ••....... •, denoted by • . ••....... •, has vertex set* .............. • ••, and there is an edge between two vertices if and only if they differ in exactly one coordinate and the difference is •. If •. • •........, then we simply write • . •• •. We estimate the search complexity of grid graphs as follows. Theorem 1.5. ••• " 1...... •• .................. As a tool, we will prove a bound on the cardinality of separators of grid graphs, using classic results from the theory of vertex isoperimetric problems and cube slicing. Theorem 1.6. The smallest • • • -biseparator of the grid graph • . •• • has cardinality • • • • We note that when considering grid graphs, one could also study the related problem that the path starting at • is monotone, i.e., if • and • are on the path and • • • (according to the usual partial order of the vectors), then the edge between • and • (if it exists) is directed towards •. In this case the needed number of queries reduces dramatically. Indeed, the trivial algorithm which follows the path uses at most •• queries. In two dimensions we could improve slightly this upper bound, yet there is a more significant improvement by Xiaoming Sun (personal communication), who proved that • •• • queries are enough in two dimensions. From below, at least • • • queries are needed regardless of • [7, Lemma 6]. This problem resembles the pyramid-path search problem (but it is not exactly the same), where also a lower bound of • is proved for the two-dimensional case [5]. Motivation. Hirsch, Papadimitriou and Vavasis [7] have proved worst-case lower bounds for finding Brouwer fixed points for algorithms using only function evaluation. They showed a lower bound that is exponential in the dimension, disproving the conjecture that Scarf's algorithm is polynomial. In our language, they have (implicitly) proved that • •• .......... • 2 ••2 • [7, Lemma 16]. Our Theorem 1.5 is an improvement of their result, although we do not use the continuous setting but rather focus only on the discretization of the problem. Later, Papadimitriou [10] considered similar complexity search problems in great detail and defined corresponding complexity classes •• • , •• •• , etc. In his model, an exponential-size graph is given by a succinct representation, i.e., by the description of a Turing-machine • . The vertices of the graph correspond to binary sequences of length • and if we input such a sequence to • , it outputs all the neighbors of the corresponding vertex in polynomial time (thus the degrees are bounded by a polynomial). Therefore, in his model, instead of considering query cost, one can work with the classical running time of the algorithm that gets • as input. If the algorithm uses • as a black box, we get back the query-cost model. D. Gerbner et al.: Search for the end of a path in the • -dimensional grid and in other graphs 305 Papadimitriou considered the problem when the maximum degree of the graph is •, i.e., it consists of vertex disjoint paths and cycles and we are also given, as part of the input, a degree-one vertex, •, and our goal is to output another degree-one vertex. This search problem is denoted by LEAF, and the complexity class •• • is defined such that LEAF is complete for •• • . (•• • stands for "Polynomial Parity Argument".) Papadimitriou introduced another variant, where the underlying graph is directed (• outputs both the in- and out-neighbors of its input in this case), the in- and out-degree of every vertex is at most one, and we are given a starting vertex • with in-degree zero and out-degree one. Therefore, the resulting digraph is the vertex-disjoint union of a directed path starting at • and possibly some other directed paths and cycles, exactly like in the problem that we study. Here our goal can be either to output an in-degree one, out-degree zero vertex (called LEAFDS problem) or an in-degree plus out-degree equals one vertex (called LE AFD problem), which means the end of a path, just like in the problem we study. Thus, the query-cost of LEAFD is exactly • •• .• •. The complexity classes for which the problems LEAFDS and LEAFD are complete are denoted, respectively, by.....and • • •• . It is easy to see that • • •• is contained in both •• • and....., while an oracle separation is known for the two latter classes [2]. Nowadays • • •• enjoys huge popularity, as several problems, among them finding an «-approximate Nash-equilibrium, turned out to be •• •• -complete. This is why this paper focuses on • •• •, the query-cost version of •• •• , though most of our results would also hold for the other variants. An extensive list of •• •• -complete problems can be found on Wikipedia. 2 Upper bounds Claim 2.1. Suppose that the connected components of • • • are •......... If every vertex of • has been queried, we know a •. which contains an endvertex (or that an endvertex is in •, hence already identified). Proof. The answers clearly show how many times we enter and leave • from each component •.. If we enter a component •. more times than we leave it, then •. must contain an endvertex. If there is no such component, the component containing • must contain an endvertex. □ This simple observation is crucial for our upper bounds and it does not hold if the answers would contain only the edges leaving the queried vertex. Proof of Theorem 1.3. Let us choose an • -multiseparator •. with ••............which cuts • into parts •........, and query all vertices of •.. By Observation 2.1 we know a part •. which contains an endvertex. Let • . be • restricted to •. and choose an • -multiseparator •. of size at most....... •••, which cuts • . into parts • ......... Then •. • •. is a separator of • , which cuts it into parts •......... .••.......... • • ......... Thus, by again using Observation 2.1 after asking every vertex of •. • •. we know which part • . contains an endvertex. After this we can continue the same way, defining • . and asking •., defining • . and asking •. and so on, until an endvertex is in some •.. As •• •• ........... . •• for any •, one can easily see that •• •• . •• • •' •• •. By the assumptions on •, • •••.•• • ........ ........" ......." ........ Altogether at most . • " ........ questions were asked. □ • ••• •••••• • 306 Ars Math. Contemp. 12 (2017) 383-413 A celebrated theorem of Lipton and Tarjan [8] states that planar graphs have separators of size at most...... Thus we have the following corollary. i • • • • • • • Corollary 2.2. If • is planar, then • Now, let us look at • -dimensional grid graphs. Miller, Teng and Vavasis [9] introduced the so-called overlap graphs for every • and proved that every member • of the class has separator of size...............•. They mention that any subset of the • -dimensional infinite grid graph belongs to the class of overlap graphs. The polynomial function..... ••....... satisfies the assumption of Theorem 1.3. Since •• •• ........', this implies that.......... ' •. Here we show that the multiplicative constant is less than 3. Theorem 2.3. • •• ....... Proof. We follow the proof of Theorem 1.3, but the cuts we use are always axis-aligned hyperplanes, which cut the current part into two smaller grid graphs. More precisely, for any • let.......,.......; now •. is a hyperplane perpendicular to the •" coordinate axis, and it cuts • .. . into two parts of size at most •• •• .. .••••. One can easily see that this is possible and ••...•• ••.•••, except if • • •, in which case ••...•• •• .•. This means that there are at most • ••• • ••• • • • • • _ queries. □ 3 Lower bounds • • • • Before proving Theorem L_6 which claims that any • • • -separator in the grid graph ' has cardinality •••"'• • •, we present a slightly weaker result, as it has a short proof not using results from the theory of isoperimetric problems. Claim 3.1. Any • -multiseparator in the grid graph • . •• • has cardinality at least •• • • •• " 1 •• for * * • • • Proof. We use induction on •. The claim is trivial for • • •. Let us denote by • an • -multiseparator. Let us choose an arbitrary axis, and denote by • the •"' ' parallel lines in the grid which go in that direction. Let • ' • • be the set of those lines which intersect • . Note that every other element of • contains vertices only from one component of • • • . If •• '........"''••, then we are done. Hence we can suppose •• '........"''••. Elements of • ' cover less than......" •• points, hence for any component • of • • • , the other components together contain at least..............." •• vertices, which are not covered by elements of • '. This means that there are at least..........."' ' •• elements of • which contain only vertices not in • . Now consider a hyperplane in the grid, orthogonal to the direction of the lines of • , and denote by • the vertices of • . •• • that belong to the hyperplane. Clearly, • contains at least..........."' ' •• elements not in • , hence • • • is an • '-multiseparator of • (with • '................) and so we can apply induction on each of these.....-dimensional hyperplanes. By induction, there are at least..........."' 2.......elements of • in every such hyperplane, which gives at least......."' '........."' ' •• elements in total. □ • • • • • • • • • D. Gerbner et al.: Search for the end of a path in the • -dimensional grid and in other graphs 307 Before proving the stronger version of this result, we need to introduce some notations and results. Let • be an arbitrary set of vertices. The set of vertices that are not in • , but are connected to some vertex of • is called the boundary of • , denoted by • • . Following the notations of Bollobas and Leader [3], we define an order on the vertices, the simplicial order, by setting • • • if •. • •., or •. • •. and for some • we have •. • •. and •. = •. for all • • •. This coincides with the lexicographic order according to the vector • • .• • •. • • •......... •. Theorem 3.2 (Bollobas and Leader [3]). In • . •• •, among sets of vertices of a given size, the initial segment of the simplicial order has the smallest boundary. The special case • • •, i.e., the hypercube, was previously treated by Harper [6], while the unbounded case of • • • was solved by Wang and Wang [13]. We note that in the paper of Bollobas and Leader the definition of boundary is different: they also include • in • • . We will also need some results about the volume of slices of a cube, i.e., intersections of the cube with specific hyperplanes. For a contemporary approach to this area we refer to [14]. In the next theorem • ' ••• denotes the following set in the • -dimensional unit cube •': • '........' • •. • • •; • ••. denotes the ^-dimensional volume of some set of dimension •. Theorem3.3 ([11,14]). ••• ... •••... • '......... f" , for each fixed' Let • . denote the • -th layer of • . •• •: the set of all vertices in • . •• • whose coordinates sum to •. The layer range from 0 to....... We define the size of the "middle-most" layers • ... by • • •• •• TOt* * * * • • • for......odd, for......even' • • •• • • • • trvr * * * • • • for......odd, for......even' In the even case, we actually know that the middle level •........ is the largest of the three levels in the definition of • ..., as the levels decrease symmetrically in size from the middle to the ends [4]. From discretizing the above theorem, one can obtain the following bound on • — Its proof can be found in Appendix B. Corollary 3.4. For every •, there exists a constant • . such that •... • • .• •••".« •••"'• and • • • ••• •••• ••• as• • • . Now we are ready to prove Theorem 1.6. Proof of Theorem 1.6. We start with the lower bound. Let us denote by • a • • • -biseparator which separates the vertex set • and • (such that.......). If........ we are 308 Ars Math. Contemp. 12 (2017) 383-413 done. Thus we suppose that.....— Denote by • ' the vertex set of size •• • which is an initial segment of the simplicial order. By Theorem 3.2 we know that............'•. By the definition of the simplicial order, • • ' is contained in the union of two successive layers • and • • •: • • ' • • . • • ., where • . • • . and • . • • .... First we claim that • must be very close to the middlemost layer. More precisely, if •• is odd, we can assume • • .., and if •• is even, we can assume • • V" • • or • • V". We treat only the odd case, the even case being similar. First, we show that • ' must reach at least level • • ■ .If • ' were disjoint from • ., we would get since the last set contains only vertices in the lower half of the levels. This contradicts the requirement fact that • • • must cover at least half of the vertices. Secondly, if • ' would contain vertices of level • • •, it would contain more than the levels.........which make up half of all vertices. This is again a contradiction to the • • • -biseparator property. By the definition of • ..., we have now established that each of the two central layers • . and • ... contains at least • ... points. To conclude the proof, we show that the separator • • ' which is contained in the two layers • . and • ... must have size at least • ... • • ••.' ' •. If a vertex • • ••........ • of • ... is not in • ., then the adjacent vertex •' defined by •' • ••.........••. • •• must be in •. unless it is not a point of the grid (i.e., •. • •): • •••••, - Since the number of vertices of • ... for which •. • • is •••"'•, we obtain • • from which the bound •• • '• • •• . • • •• . • • • ... • •••"'• follows. For the upper bound, we simply take the central layer •..........of size • V" as a biseparator. □ Now we are ready to prove Theorem 1.2, that • b i....... •• •. Proof of Theorem 1.2. We will use an adversary argument for the lower bound on the number of queries. The adversary will try to answer the queries in such a way that the discovery of the endvertex by the searcher is delayed as much as possible. The adversary need not choose a path • in advance, but it is required that the answers remain consistent with some path. Let • denote the vertices that have been queried so far in the search. We will show that the adversary can achieve that after the other end of the path is found, • becomes a • • • -biseparator. The adversary maintains a component • of • • • , see Figure 1. • is the set of vertices which can possibly be the endvertex of the path. (The adversary will follow a greedy strategy of keeping this set as large as possible.) In addition to • , the adversary maintains a path • between • and some vertex • • • , which will be part of the final path and for which........ The remaining components of • • • are partitioned into two sets...........such that both • and • contain at most.....vertices and there are no edges between • and • . Thus we always have a partition into four disjoint sets • • • • • • • • • . The adversary can reveal all these data to the searcher as free additional information. Initially, • • • , • • • and........ D. Gerbner et al.: Search for the end of a path in the • -dimensional grid and in other graphs 309 Figure 1: A schematic drawing of the situation maintained by the adversary. The queried vertices, • , are marked by squares. Figure 2: Updating the set • after a query • The strategy is the following. If the queried vertex • is in • , the adversary repeats the previous answer for this vertex. If......., the adversary answers by reporting the ingoing and outgoing edge of • at that vertex. If • • • • • , then the answer is that "the path does not pass through this vertex." In these cases, no new information is revealed to the searcher. The vertex •, the set • , and the path • remain unchanged; the only change is that • is moved from • • • to • . Let us now look at the case • • • . Let........ • • ........ be the partition of.....into • • • connected components. The adversary chooses a largest component • ., and will answer in such a way that the new set • becomes • • • .. Therefore, if • contains •, the answer is again "the path does not pass through this vertex," see Figure 2 (a). The current endpoint • and the path • are unchanged. If • does not contain • (including the case • • •), then choose •• • to be a neighbor of • , see Figure 2 (b). As • was a possible endpoint of the path before this step, there is a path • from • to • which lies in • • • . The adversary uses • and the edge • •to extend the path • to a longer path • . (This is the only case when the path is updated.) The adversary reports the last arc of • as the ingoing arc at • and ••as the outgoing arc. 310 Ars Math. Contemp. 12 (2017) 383-413 To maintain the invariant that............., we go through the components • . • • one by one and add them either to • or to • (to eventually obtain • and • ), whichever is smaller. If, for example,......., then...................... as ••• .•• •• are disjoint subsets of • . Therefore, the invariant is maintained. The searcher can only identify •, the end of the path, when •• • becomes •. By assumption, the graph • has at least two vertices and is connected, and therefore • • •. Thus, at this point, We can now add the singleton set.....to the smaller of • and • without exceeding the size bound...... The set • of queried vertices forms thus a • • • -biseparator. □ Corollary 3.5. • p •• d ** ** • • •* • • • Theorem 1.5 summarizes the above results. The lower and upper bounds are quite close. Specifically, if we consider • as fixed, then the theorem gives exact asymptotics in • for the needed number of queries. 4 Concluding Remarks: Problem Variations Here we mention three more variants of the problem. In the first variant, we consider any directed subgraph of • ' and a vertex • with larger out-degree than in-degree. In this version there is a vertex with higher in-degree than out-degree, our goal is to find such a vertex. All of our algorithms work in this case, and obviously the same lower bounds hold. In the second variant, • consists of directed paths and cycles, but we also assume that they cover every vertex. This is a special case of our model, hence the upper bounds hold. However, a lower bound similar to Theorem 1.2 is not plausible, as there are graphs that have only big separators, yet there are only a few valid choices for • . For example if • contains a vertex of degree one, different from the source, then this vertex must be the endvertex. But in case of grid graphs we can show that the additional assumption on • does not make the problem much easier. Denote by •. •• • the minimum number of queries needed to find an endvertex in the worst-case for any • • • . Now we show how to give a lower bound for •. •• .••••. Let us suppose we are given an •. • •. • •........ grid graph • . Then let • 4" denote the • • • •. grid graph. • • • • • Theorem 4.1. Let • be a grid graph. Then • •••• • •• The proof of this theorem can be found in Appendix C. One can easily see that if 4 divides • and • is the...............grid graph, then • ....... We need a lower bound on the size of separators in • .It is easy to see that if we replace every vertex of • by 16 vertices to get • .••••, an • -separator is replaced by an • -separator, hence the same lower bound of •••"'• • •, divided by 16, holds for Corollary 4.2. D. Gerbner et al.: Search for the end of a path in the • -dimensional grid and in other graphs 311 In the third variant, • is undirected. Our goal is to find another endvertex and the answer to the query is the at most two incident edges. Obviously, this is a harder problem than the directed variant. Hence our lower bounds hold, and one can easily modify our proofs to get the same upper bounds as well. For example, in Observation 2.1, the endvertex is in the component •. which is connected to • by an odd number of edges, counting an extra edge for the component of •. Finally, a straightforward application of our proofs gives the asymptotics to a question recently asked on MathOverflow [1], which is the following. Given a path • . from the bottom-left vertex of an • • • grid to its top-right vertex, and another path • . from its top-left vertex to its bottom-right vertex, how many queries are needed to find a vertex contained in both paths? 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The total weight of the tree becomes • • • •• •, which is very near to a power of 3. In ternary notation,............ with • twos, and the ideal weight for the halves of the biseparator is................. After removing a separating set, any union of components of the complement can be represented as a sum and difference of subtrees. Here, by a subtree we mean a node together with all its descendants. If the separator has • nodes, we must be able to group the resulting components into a set that has between.....and •• • nodes, i.e., weight between • • • • and • . Each separator node creates at most four new subtrees from which the sum and difference can be formed: its own subtree and the three children subtrees. (These latter ones exist only if the node was not a leaf.) So with • separating nodes, we get • • • • subtrees from which to form the sum and difference. Each tree has a weight of the form • * • • If we take a sum and difference of......subtrees we must fulfill the inequality which implies and For any number • in the range..............., the ternary representation starts with at least................ones. On the other hand, one easily sees by induction that a sum and difference of • powers of 3 has at most • ones in its ternary representation. We thus get the relation......................., from which...... follows. □ B Proof of Corollary 3.4 We show that for any fixed • • • (and then by symmetry for every • • • too), whenever ..........is an integer, •• • ^ • ••• •••• • D. Gerbner et al.: Search for the end of a path in the • -dimensional grid and in other graphs 313 We define • . • •••... • '....., i.e., the volume of the middle slice jaf the unit hypercube. Setting • • • in Theorem 3.3 establishes the convergence of • . to • •• . The layer • ., for............, is a discrete version of a slice of a cube. If we fix the first • • • coordinates, then there is at most one vertex in • . that has these first • • • coordinates. Thus •• . • • •• . •, where • . is the projection of • . along the last axis. To estimate the size of • . (and thus of • . ) take first the middle slice • '.....of the continuous unit cube and project it to the first • • • coordinates, yielding the polytope • '.....'. As the normal vector of the slice is..........., projecting it to the hyperplane orthogonal to the last axis scales the volume by a factor of • • • : » •• • Now let • '....." • •• '.....', i.e., we blow up • '.....' by a factor ».Let • be the set of grid points in this • '.....". As for fixed •, • '....." is a factor-» blow up of some fixed.....-dimensional convex polytope, the difference between its volume and the number of grid points in it is • ••"'•. (This follows basically from the definition of the volume, for details see e.g., [12, Proposition 4.6.13].) Thus, •• • • •*** • •• ^ • *•••••* • • ••***•• • • " 1 2 " 2 2 ♦ 1 " 2 • • • • • •• • • • • • •• • • •• Now we are left to show that •• k........." 2 •. For that it is enough to show that •• k • • • and •• • • k • are • • • " 2 •. For all of these points the sum of the • • • coordinates is equal to..........(resp.............) for some...... This is • •• " 2 • points for every •, altogether..... 2 2 2 ..... 2 2 2 • points, which finishes the proof. □ C Proof of Theorem 4.1 Suppose we are given a grid graph • and an Algorithm A which finds • in • 2 22 in case one path and some cycles cover every vertex. We show an Algorithm B which finds the endvertex in • in case there is only a directed path. We can naturally identify every vertex of • with a • • • grid in • 2 22 : the vertex • • ••1.....2 • corresponds to the axis-parallel • • • rectangle (we call it a block) • •• • having •• vertices, whose two opposite corners are•••1.....2 • •••......"• and•••1*•v"......2v We call•••1.....2 • •••......"• and •••1 • •v......2 • the even corners and the two other corners •• •1.....2 ••......2 • and •• •1 • • v • • • .......2 • the odd corners. Consider a directed path • in • . We call a system of a directed path and some directed cycles in • 2 22 good if they cover every vertex and the path goes through exactly those blocks which correspond to the vertices of • , in the same order. Now we construct good systems. If a vertex......is not on the path, we cover the corresponding block by a cycle. In case of a vertex • • ••1......2 • on the path in • , the directed path arrives at the corresponding block • •• • in some corner • 1 •• •, and goes straight to a neighboring corner • 2 •• •, where it leaves. The remaining vertices form a • • • rectangle, which can be covered by a cycle. Finally, when • is the very last vertex on the path, we define • 1 •• • similarly, and cover the remaining vertices by a path starting in •1 •• •. Our good systems will ^satisfy an additional property. If, for a vertex • • ••1.....2 • of • , the coordinate sum 2=. •. is even, then the first vertex • 1 •• • of the path in the . • • • • • • 314 Ars Math. Contemp. 12 (2017) 383-413 corresponding block is an even corner, and the last vertex •. •• • is an odd corner. In case ... •. is odd, it is the other way round. Note that if it is true for • •• •, it has to be true for every other block as well. Indeed, when the path leaves a block at, for example, an odd corner, it either moves in one of the first two dimensions (then it arrives at an even corner, and ... •. does not change), or in another dimension (then it arrives at an odd corner, .. 3 but the parity of .d.3 •. changes). Note that these properties do not uniquely determine the system. We will incrementally determine the graph as queries arrive. Now we are ready to define Algorithm B. At every step we call Algorithm A, and then answer such a way that at the end we get a good system. If Algorithm A would query a vertex • in • "', Algorithm B queries the corresponding vertex •' in • instead (i.e., the vertex •' with.....'•). Using the answer for this query, we choose all the edges incident to vertices of • •• '• and answer to Algorithm A according to this. If •' has been asked before, we have already determined the edges in • ••'•, and answer accordingly. Suppose that •' has not been queried before. In case the answer is that •' is not on the path, choose an arbitrary cycle covering the vertices of the corresponding block • •• '• and answer according to the edges incident to • . In case the answer gives two arcs ••' and • , we have to choose the entering vertex •.••'• and the exit vertex •. ••'•. We will discuss this choice below. This choice will define 5 edges on the path and a cycle of length 12. One edge connects the blocks corresponding to • and •, leaving the last vertex of the path in • •• • and arriving at the first vertex of the path in • •• '•, i.e., this edge is •.••••. •• '•. Similarly we add the edge •. •• '••. •• •. We also add the three edges which connect •. ••'• and •. ••'•. Finally we cover the remaining 12 vertices with a cycle. We still have to tell which one of the two possible first vertices we use as •. •• '•, and similarly for the possible last vertices. If •. •• • has already been determined, this fixes the choice of •.••'• as the vertex adjacent to it. If ••' is parallel to one of the first two axes, this also reduces the choice of the corner •.••'• to one possibility. Otherwise we pick •.••'• arbitrarily among the two choices. The exiting vertex •. ••'• is determined analogously. Even if Algorithm A would know all answers in • •• '•, it does not give more information than what Algorithm B knows after asking •'. Algorithm A does not finish before Algorithm B finds the end vertex, thus Algorithm A needs at least as many queries as Algorithm B (on the respective graphs), which finishes the proof. □